4[x-(4-x)]-7(x+1)=0

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Solution for 4[x-(4-x)]-7(x+1)=0 equation:


Simplifying
4[x + -1(4 + -1x)] + -7(x + 1) = 0
4[x + (4 * -1 + -1x * -1)] + -7(x + 1) = 0
4[x + (-4 + 1x)] + -7(x + 1) = 0

Reorder the terms:
4[-4 + x + 1x] + -7(x + 1) = 0

Combine like terms: x + 1x = 2x
4[-4 + 2x] + -7(x + 1) = 0
[-4 * 4 + 2x * 4] + -7(x + 1) = 0
[-16 + 8x] + -7(x + 1) = 0

Reorder the terms:
-16 + 8x + -7(1 + x) = 0
-16 + 8x + (1 * -7 + x * -7) = 0
-16 + 8x + (-7 + -7x) = 0

Reorder the terms:
-16 + -7 + 8x + -7x = 0

Combine like terms: -16 + -7 = -23
-23 + 8x + -7x = 0

Combine like terms: 8x + -7x = 1x
-23 + 1x = 0

Solving
-23 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '23' to each side of the equation.
-23 + 23 + 1x = 0 + 23

Combine like terms: -23 + 23 = 0
0 + 1x = 0 + 23
1x = 0 + 23

Combine like terms: 0 + 23 = 23
1x = 23

Divide each side by '1'.
x = 23

Simplifying
x = 23

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